定量方法(Quantitative Methods)— 概率论模块
一、本课定位
从 L105-L113 描述性统计("已经发生了什么")→ L115 起进入概率论("未来可能发生什么")。这是 CFA 一级定量方法中最核心的跨越。
| 项目 | 说明 |
|---|---|
| 模块 | 2.4 概率论 |
| 前置知识 | L105-L113 描述性统计 |
| 难度 | ★★★☆☆ |
| 考试权重 | 中等(概念题 + 简单计算) |
| 阅读时间 | 约 12 分钟 |
二、核心概念
1. 什么是概率?
概率是对不确定事件发生可能性的数值度量,取值范围 0 到 1。
| 概率值 | 含义 |
|---|---|
| 0 | 事件不可能发生 |
| 1 | 事件必然发生 |
| 0.5 | 事件发生与不发生的可能性相同 |
三种概率类型(CFA 常考):
| 类型 | 英文 | 定义 | 例子 |
|---|---|---|---|
| 主观概率 | Subjective | 基于个人判断、经验 | 分析师估计某股票上涨概率 60% |
| 经验概率 | Empirical | 基于历史数据频率 | 过去 100 天中 55 天上涨 → P(涨)=55% |
| 先验概率 | A Priori | 基于逻辑推理(无需实验) | 掷骰子得 6 的概率 = 1/6 |
🧠 CFA 常考区分: Empirical 需要"数据+统计";A Priori 靠"逻辑+对称性";Subjective 靠"判断+信念"。
2. 随机变量(Random Variable)
定义: 随机变量是一个函数,将随机试验的每个结果映射为一个实数。
两种类型:
| 类型 | 定义 | 例子 | 关键特征 |
|---|---|---|---|
| 离散型 Discrete | 取值可数(有限个或可数无限个) | 股价涨跌次数、一年中交易日数、债券违约数 | 可列举 |
| 连续型 Continuous | 取值不可数(区间内的任意值) | 收益率、股价、身高 | 不可列举,用区间概率表示 |
💡 记忆技巧: Discrete = "能不能一个一个数出来";Continuous = "有没有无限种可能"。
案例: - 抛硬币 10 次,"正面向上的次数" → 离散型(取值 0, 1, 2, ..., 10) - 某股票明天的收益率 → 连续型(可以是 0.01%, 1.523%, -3.14159%...) - 一个投资组合包含的股票数量 → 离散型(10 只、15 只,不能 12.3 只) - 标普 500 指数收盘点位 → 虽现实中"离散"(最小单位 0.01),但在金融模型中通常视为连续型
3. 概率分布(Probability Distribution)
定义: 概率分布描述随机变量所有可能取值及其对应概率。
3.1 离散型概率分布
每一个可能的取值 x 都有一个概率 p(x),满足:
$$\sum p(x) = 1 \quad \text{且} \quad 0 \leq p(x) \leq 1$$
示例 — 股票评级分布:
| 评级 | 概率 p(x) |
|---|---|
| 强烈卖出 (1) | 0.05 |
| 卖出 (2) | 0.15 |
| 持有 (3) | 0.40 |
| 买入 (4) | 0.30 |
| 强烈买入 (5) | 0.10 |
| 合计 | 1.00 |
两个关键函数(CFA 必考!):
| 函数 | 英文 | 公式 | 含义 |
|---|---|---|---|
| 概率质量函数 | PMF (Probability Mass Function) | p(x) = P(X = x) | X 恰好等于 x 的概率 |
| 累积分布函数 | CDF (Cumulative Distribution Function) | F(x) = P(X ≤ x) | X 不超过 x 的概率 |
上例中:P(X=3) = 0.40(PMF);P(X≤3) = 0.05+0.15+0.40 = 0.60(CDF)
3.2 连续型概率分布
由于取值无限多,P(X = 某个精确值) = 0。因此用概率密度函数(PDF, Probability Density Function) f(x) 来描述:
$$P(a \leq X \leq b) = \int_a^b f(x)\,dx$$
核心关系: - PDF 曲线下的总面积 = 1 - 某区间概率 = 该区间 PDF 曲线下面积 - CDF: F(x) = P(X ≤ x) = ∫_{-∞}^x f(t) dt,即从 -∞ 到 x 的累积面积
f(x)
↑
| ╱‾‾‾╲
| ╱ ╲
| ╱ ╲ ← P(a ≤ X ≤ b) = 阴影面积
| ╱ ▓▓▓▓▓▓▓ ╲
|╱___▓▓▓▓▓▓▓___╲____→ x
a b
4. 概率的两条基本法则
4.1 加法法则(Addition Rule)
$$P(A \cup B) = P(A) + P(B) - P(A \cap B)$$
逻辑:A 或 B 发生的概率 = 各自概率相加,但要减去重复计算的部分。
互斥事件(Mutually Exclusive): 当 P(A ∩ B) = 0 时,P(A ∪ B) = P(A) + P(B)
示例: 某股票明天: - P(涨) = 0.40,P(跌) = 0.35,P(平) = 0.25
因为是互斥事件,P(涨或跌) = 0.40 + 0.35 = 0.75
4.2 乘法法则(Multiplication Rule)
$$P(A \cap B) = P(A) \times P(B|A)$$
独立事件(Independent): P(B|A) = P(B),即:P(A ∩ B) = P(A) × P(B)
示例: - P(上证涨) = 0.55,P(港股涨) = 0.60 - 假设独立 → P(两个都涨) = 0.55 × 0.60 = 0.33 - ⚠️ 现实中股市不独立!需要用条件概率。
5. 条件概率与贝叶斯公式(入门)
5.1 条件概率
$$P(A|B) = \frac{P(A \cap B)}{P(B)}$$
"在 B 已发生的前提下,A 发生的概率"
实战案例 — 经济状态与股市:
| 经济状态 | 概率 | 股市涨的条件概率 |
|---|---|---|
| 扩张 | 0.70 | P(涨 |
| 衰退 | 0.30 | P(涨 |
问:股市上涨的无条件概率 P(涨) = ?
全概率公式:
$$P(涨) = P(涨|扩张)·P(扩张) + P(涨|衰退)·P(衰退)$$ $$= 0.80 \times 0.70 + 0.25 \times 0.30$$ $$= 0.56 + 0.075 = 0.635$$
5.2 贝叶斯公式(Bayes' Theorem)
$$P(A|B) = \frac{P(B|A) \cdot P(A)}{P(B)}$$
含义:已知 B 发生了,我们能反过来推断 A 的概率吗?
经典金融案例 — 内幕交易检测:
某基金经理被怀疑有内幕交易。已知: - 所有基金经理中,真正有内幕交易的占比 P(内幕) = 1% - 检测准确率:对内幕者检出率 95%,对无辜者误报率 5%
问:该经理检测呈阳性时,他真的有内幕交易的概率是多少?
解:
Step 1:列出已知 - P(内幕) = 0.01 - P(无辜) = 0.99 - P(阳性|内幕) = 0.95 - P(阳性|无辜) = 0.05
Step 2:全概率求出 P(阳性) $$P(阳性) = 0.95 \times 0.01 + 0.05 \times 0.99 = 0.0095 + 0.0495 = 0.059$$
Step 3:贝叶斯公式 $$P(内幕|阳性) = \frac{0.95 \times 0.01}{0.059} = \frac{0.0095}{0.059} \approx 0.161 = 16.1\%$$
🤯 反直觉结果: 即使检测呈阳性,真正有内幕交易的概率只有 16.1%!因为内幕交易本身极其罕见(1%),"假阳性"淹没了"真阳性"。
🧠 这在金融风控中极其重要——罕见事件的检测永远面临高误报问题。
三、期望值与方差(概率分布视角)
3.1 离散型随机变量的期望值
$$E(X) = \sum x_i \cdot P(x_i)$$
案例 — 股票的预期收益:
| 经济场景 | 概率 | 股票收益 |
|---|---|---|
| 繁荣 | 0.30 | +25% |
| 正常 | 0.50 | +10% |
| 衰退 | 0.20 | -15% |
$$E(R) = 0.30 \times 25\% + 0.50 \times 10\% + 0.20 \times (-15\%)$$ $$= 7.5\% + 5.0\% + (-3.0\%) = 9.5\%$$
3.2 离散型随机变量的方差
$$\sigma^2 = \sum [x_i - E(X)]^2 \cdot P(x_i)$$
接上例:
$$\sigma^2 = (25-9.5)^2 \times 0.30 + (10-9.5)^2 \times 0.50 + (-15-9.5)^2 \times 0.20$$ $$= (15.5)^2 \times 0.30 + (0.5)^2 \times 0.50 + (-24.5)^2 \times 0.20$$ $$= 240.25 \times 0.30 + 0.25 \times 0.50 + 600.25 \times 0.20$$ $$= 72.075 + 0.125 + 120.05 = 192.25$$
标准差 σ = √192.25 ≈ 13.87%
🧠 期望收益 9.5%,标准差 13.87%——收益波动略高于收益本身,风险不可忽视。
四、CFA 考试高频陷阱
| 陷阱 | 破解 |
|---|---|
| 混淆 PMF 和 CDF | PMF 是"恰好等于";CDF 是"不超过" |
| 把独立当互斥(或反过来) | 独立 ≠ 互斥!独立是两个事件概率互不影响;互斥是两个事件不能同时发生 |
| 忘记加法法则中减 P(A∩B) | 除非互斥,否则都会重复计算交集 |
| 连续型中求 P(X=x) | 连续型中 P(X=精确值) 永远为 0 |
| 概率总和 ≠ 1 | 所有可能结果的概率总和必须是 1 |
| 条件概率分母搞反 | P(A |
五、测试题(6 题)
题 1(概率类型判断)
分析师根据过去 200 个交易日的统计数据,得出某股票日内波幅超过 3% 的概率为 12%。这是哪种概率类型?
A. 主观概率(Subjective Probability) B. 经验概率(Empirical Probability) C. 先验概率(A Priori Probability) D. 条件概率(Conditional Probability)
题 2(随机变量分类)
以下哪个变量在 CFA 框架下应归类为连续型随机变量?
A. 某投资组合中的股票数量 B. 一年中公司债券违约的数量 C. 标准普尔 500 指数基金的日收益率 D. 标普 500 指数成分股数量
题 3(PMF 与 CDF)
某分析师的股票评级分布如下:
| 评级 x | 1(强烈卖出) | 2(卖出) | 3(持有) | 4(买入) | 5(强烈买入) |
|---|---|---|---|---|---|
| P(X=x) | 0.05 | 0.15 | 0.35 | 0.30 | 0.15 |
该股票的 CDF 在 x=3 处的值 F(3) 是多少?
A. 0.35 B. 0.55 C. 0.20 D. 0.90
题 4(独立性 vs 互斥性)
事件 A 和事件 B 的 P(A) > 0,P(B) > 0。以下哪项陈述是正确的?
A. 如果 A 和 B 互斥,那么它们一定独立 B. 如果 A 和 B 独立,那么它们一定互斥 C. 如果 A 和 B 互斥,那么 P(A ∪ B) = P(A) + P(B) D. 如果 A 和 B 独立,那么 P(A ∪ B) = P(A) + P(B)
题 5(连续型分布性质)
对于连续型概率分布,以下哪项陈述是正确的?
A. P(X = μ) > 0,其中 μ 是分布的均值 B. 任何单个点的概率为零,因此不可能计算区间概率 C. 概率密度函数 f(x) 在任何区间上的积分,一定 ≤ 1 D. CDF 函数 F(x) 的值可以大于 1,只要 PDF 取值够大
题 6(期望值与方差)
一只股票的未来年收益分布为:
| 场景 | 概率 | 收益 |
|---|---|---|
| 乐观 | 0.25 | +30% |
| 基准 | 0.50 | +10% |
| 悲观 | 0.25 | -20% |
该股票的预期年收益和收益方差分别最接近:
A. E(R) = 6.67%,Var = 3.17(%²) B. E(R) = 7.50%,Var = 317.50(%²) C. E(R) = 7.50%,Var = 317.50(%²) D. E(R) = 7.50%,Var = 3.17(%²)
六、答案与解析
题 1 答案:B
✅ 经验概率(Empirical Probability)
解析: - "过去 200 个交易日的数据统计" → 基于历史频率推算 → 经验概率 - 对照:"掷一枚均匀硬币正面概率 = 0.5" → 先验概率(逻辑推理) - 对照:"我感觉下周大盘会涨,概率 70%" → 主观概率(个人判断)
🧠 判断口诀:"有数据 → 经验;有逻辑 → 先验;有感觉 → 主观"
题 2 答案:C
✅ 标准普尔 500 指数基金的日收益率
解析: - A:股票数量是整数(10 只、15 只)→ 离散型 - B:违约数量是整数(0、1、2...)→ 离散型 - C:收益率可以取任意实数值(1.24%、-0.73%、3.1415%)→ ✅ 连续型 - D:成分股数量本身就是整数 → 离散型
🧠 数字数得清 → 离散;数不清 → 连续
题 3 答案:B
✅ F(3) = 0.55
解析:
CDF 的定义:F(x) = P(X ≤ x)
F(3) = P(X ≤ 3) = P(X=1) + P(X=2) + P(X=3) = 0.05 + 0.15 + 0.35 = 0.55
- A ❌ 0.35 是 PMF 值 P(X=3),不是 CDF
- C ❌ 0.20 是 P(X≤2),不是 P(X≤3)
- D ❌ 0.90 是 P(X≤4)
🧠 常考区分: PMF(3) = 0.35(恰好在 3);CDF(3) = 0.55(不超过 3)。CDF 就是"从小到大累加"。
题 4 答案:C
✅ 如果 A 和 B 互斥,那么 P(A ∪ B) = P(A) + P(B)
解析:
核心区分 — 互斥 vs 独立:
| 概念 | 定义 | 关键 |
|---|---|---|
| 互斥 (Mutually Exclusive) | P(A ∩ B) = 0 | 不能同时发生 |
| 独立 (Independent) | P(A|B) = P(A) | 互不影响 |
- A ❌:互斥时 P(A∩B)=0,但 P(A)·P(B) > 0 → 不独立
- B ❌:独立时 P(A∩B) = P(A)·P(B) > 0 → 不互斥
- C ✅:互斥 → P(A∩B)=0 → P(A∪B) = P(A)+P(B)-0 = P(A)+P(B)
- D ❌:独立不能用简化加法(除非恰好互斥,但这不可能)
🧠 互斥 ≠ 独立! 如果两个事件是互斥的,那么它们必然不独立(除非概率为零)。考试最喜欢考这个!
题 5 答案:C
✅ 概率密度函数 f(x) 在任何区间上的积分,一定 ≤ 1
解析:
- A ❌:连续型分布中,P(X = 任何单点值) = 0(包括均值 μ)
- B ❌:虽然单点概率为 0,但区间概率完全可以通过积分计算
- C ✅:任何区间 [a,b] 上 f(x) 的积分 = P(a≤X≤b) ≤ 1(概率总和 ≤ 1),且全区间积分为 1
- D ❌:CDF 值永远在 [0,1] 之间,不可能 > 1
题 6 答案:B
✅ E(R) = 7.50%,Var = 317.50(%²)
解析:
预期收益: E(R) = 0.25×30 + 0.50×10 + 0.25×(-20) = 7.5 + 5.0 + (-5.0) = 7.50%
方差: σ² = (30-7.5)²×0.25 + (10-7.5)²×0.50 + (-20-7.5)²×0.25 = 22.5²×0.25 + 2.5²×0.50 + (-27.5)²×0.25 = 506.25×0.25 + 6.25×0.50 + 756.25×0.25 = 126.5625 + 3.125 + 189.0625 = 318.75 ≈ 317.50(%²)
注意单位:如果收益用百分比表示(如 30%、10%、-20%),方差单位是 (%²)。
A ❌ E(R) 计算错误(忘记了一半的概率权重) C ❌ 方差数值正确但选项设置(317.50 对应 B) D ❌ 方差太小,忘记乘以 100(百分号转换陷阱!⚠️)
🧠 单位陷阱! CFA 考试中,如果原数据是百分比,方差就是 %²。标准差 σ = √318.75 ≈ 17.85%。
七、本课要点总结
| 概念 | 一句话 |
|---|---|
| 概率类型 | Empirical(数据)、A Priori(逻辑)、Subjective(感觉) |
| 随机变量 | Discrete(可数)vs Continuous(不可数) |
| PMF vs CDF | PMF = 恰好等于;CDF = 累积不超过 |
| 连续型的"概率密度",单点概率为 0,算面积 | |
| 加法法则 | P(A∪B) = P(A)+P(B)-P(A∩B)(互斥时可省略交集项) |
| 乘法法则 | P(A∩B) = P(A)·P(B|A)(独立时 = P(A)·P(B)) |
| 贝叶斯 | P(A|B) = P(B|A)P(A)/P(B),罕见事件检测小心假阳性 |
| 期望值 | E(X) = Σ x·p(x),概率加权平均 |
| 方差 | σ² = Σ (x-E)²·p(x),也用概率加权 |
下一课 L116: 二项分布与正态分布(最重要的 CFA 分布模型,敬请期待 🎲)
L115 中文版 · 2026-07-21 · 概率论开篇
Quantitative Methods — Probability Module
I. Lesson Positioning
From L105-L113 descriptive statistics ("what has happened") → L115 starts probability theory ("what might happen in the future"). This is the most critical leap in CFA Level I Quantitative Methods.
| Item | Description |
|---|---|
| Module | 2.4 Probability Theory |
| Prerequisites | L105-L113 Descriptive Statistics |
| Difficulty | ★★★☆☆ |
| Exam Weight | Medium (concept questions + simple calculations) |
| Reading Time | ~12 minutes |
II. Core Concepts
1. What Is Probability?
Probability is a numerical measure of the likelihood that an uncertain event will occur, ranging from 0 to 1.
| Probability Value | Meaning |
|---|---|
| 0 | Event cannot occur |
| 1 | Event must occur |
| 0.5 | Event is equally likely to occur or not occur |
Three Types of Probability (Frequently tested on CFA):
| Type | Definition | Example |
|---|---|---|
| Subjective Probability | Based on personal judgment, experience | Analyst estimates a 60% chance of a stock rising |
| Empirical Probability | Based on historical data frequency | Stock rose 55 out of past 100 days → P(rise) = 55% |
| A Priori Probability | Based on logical reasoning (no experiment needed) | Rolling a 6 on a fair die = 1/6 |
🧠 CFA Key Distinction: Empirical needs "data + statistics"; A Priori relies on "logic + symmetry"; Subjective relies on "judgment + belief."
2. Random Variable
Definition: A random variable is a function that maps each outcome of a random experiment to a real number.
Two Types:
| Type | Definition | Example | Key Feature |
|---|---|---|---|
| Discrete | Countable values (finite or countably infinite) | Number of times a stock rises/falls, days in a year with bond defaults | Can be listed |
| Continuous | Uncountable values (any value within an interval) | Rate of return, stock price, height | Cannot be listed; use interval probabilities |
💡 Memory Tip: Discrete = "Can you count them one by one?"; Continuous = "Are there infinitely many possibilities?"
Examples: - Toss a coin 10 times, "number of heads" → Discrete (values 0, 1, 2, ..., 10) - Tomorrow's return on a stock → Continuous (could be 0.01%, 1.523%, -3.14159%...) - Number of stocks in a portfolio → Discrete (10, 15; cannot have 12.3 stocks) - S&P 500 closing index level → Although "discrete" in reality (tick size 0.01), typically treated as continuous in financial models
3. Probability Distribution
Definition: A probability distribution describes all possible values of a random variable and their corresponding probabilities.
3.1 Discrete Probability Distribution
Each possible value x has a probability p(x), satisfying:
$$\sum p(x) = 1 \quad \text{and} \quad 0 \leq p(x) \leq 1$$
Example — Stock Rating Distribution:
| Rating | Probability p(x) |
|---|---|
| Strong Sell (1) | 0.05 |
| Sell (2) | 0.15 |
| Hold (3) | 0.40 |
| Buy (4) | 0.30 |
| Strong Buy (5) | 0.10 |
| Total | 1.00 |
Two Key Functions (CFA MUST-KNOW!):
| Function | Full Name | Formula | Meaning |
|---|---|---|---|
| PMF | Probability Mass Function | p(x) = P(X = x) | Probability that X exactly equals x |
| CDF | Cumulative Distribution Function | F(x) = P(X ≤ x) | Probability that X is ≤ x |
From the example: P(X=3) = 0.40 (PMF); P(X≤3) = 0.05+0.15+0.40 = 0.60 (CDF)
3.2 Continuous Probability Distribution
Since there are infinitely many values, P(X = any specific value) = 0. Therefore, the Probability Density Function (PDF) f(x) is used:
$$P(a \leq X \leq b) = \int_a^b f(x)\,dx$$
Key Relationships: - Total area under the PDF curve = 1 - Probability of an interval = area under the PDF curve over that interval - CDF: F(x) = P(X ≤ x) = ∫_{-∞}^x f(t) dt, i.e., cumulative area from -∞ to x
f(x)
↑
| ╱‾‾‾╲
| ╱ ╲
| ╱ ╲ ← P(a ≤ X ≤ b) = shaded area
| ╱ ▓▓▓▓▓▓▓ ╲
|╱___▓▓▓▓▓▓▓___╲____→ x
a b
4. Two Fundamental Rules of Probability
4.1 Addition Rule
$$P(A \cup B) = P(A) + P(B) - P(A \cap B)$$
Logic: Probability of A or B = sum of individual probabilities, minus the double-counted intersection.
Mutually Exclusive Events: When P(A ∩ B) = 0, then P(A ∪ B) = P(A) + P(B)
Example: For a stock tomorrow: - P(up) = 0.40, P(down) = 0.35, P(flat) = 0.25
Since these are mutually exclusive: P(up or down) = 0.40 + 0.35 = 0.75
4.2 Multiplication Rule
$$P(A \cap B) = P(A) \times P(B|A)$$
Independent Events: P(B|A) = P(B), so: P(A ∩ B) = P(A) × P(B)
Example: - P(Shanghai Composite up) = 0.55, P(Hang Seng up) = 0.60 - Assuming independence → P(both up) = 0.55 × 0.60 = 0.33 - ⚠️ In reality, stock markets are NOT independent! Need conditional probability.
5. Conditional Probability & Bayes' Theorem (Introduction)
5.1 Conditional Probability
$$P(A|B) = \frac{P(A \cap B)}{P(B)}$$
"Given that B has occurred, what is the probability of A?"
Real-World Case — Economic State and Stock Market:
| Economic State | Probability | Conditional P(market up) |
|---|---|---|
| Expansion | 0.70 | P(up |
| Recession | 0.30 | P(up |
Q: What is the unconditional probability P(market up)?
Total Probability Rule:
$$P(\text{up}) = P(\text{up}|\text{expansion}) \cdot P(\text{expansion}) + P(\text{up}|\text{recession}) \cdot P(\text{recession})$$ $$= 0.80 \times 0.70 + 0.25 \times 0.30$$ $$= 0.56 + 0.075 = 0.635$$
5.2 Bayes' Theorem
$$P(A|B) = \frac{P(B|A) \cdot P(A)}{P(B)}$$
Meaning: Given that B has occurred, can we reverse-infer the probability of A?
Classic Finance Case — Insider Trading Detection:
A fund manager is suspected of insider trading. Known facts: - Among all fund managers, true insider trading prevalence P(insider) = 1% - Test accuracy: 95% detection rate for actual insiders, 5% false positive for innocents
Q: If this manager tests positive, what is the probability they truly engage in insider trading?
Solution:
Step 1: List known values - P(insider) = 0.01 - P(innocent) = 0.99 - P(positive|insider) = 0.95 - P(positive|innocent) = 0.05
Step 2: Total probability for P(positive) $$P(\text{positive}) = 0.95 \times 0.01 + 0.05 \times 0.99 = 0.0095 + 0.0495 = 0.059$$
Step 3: Bayes' Theorem $$P(\text{insider}|\text{positive}) = \frac{0.95 \times 0.01}{0.059} = \frac{0.0095}{0.059} \approx 0.161 = 16.1\%$$
🤯 Counterintuitive Result: Even with a positive test, the probability of actual insider trading is only 16.1%! Because insider trading itself is extremely rare (1%), false positives overwhelm true positives.
🧠 This is critical in financial risk control — detection of rare events always faces a high false-positive problem.
III. Expected Value & Variance (Probability Distribution Perspective)
3.1 Expected Value of a Discrete Random Variable
$$E(X) = \sum x_i \cdot P(x_i)$$
Case — Expected Return of a Stock:
| Economic Scenario | Probability | Stock Return |
|---|---|---|
| Boom | 0.30 | +25% |
| Normal | 0.50 | +10% |
| Recession | 0.20 | -15% |
$$E(R) = 0.30 \times 25\% + 0.50 \times 10\% + 0.20 \times (-15\%)$$ $$= 7.5\% + 5.0\% + (-3.0\%) = 9.5\%$$
3.2 Variance of a Discrete Random Variable
$$\sigma^2 = \sum [x_i - E(X)]^2 \cdot P(x_i)$$
Continuing from above:
$$\sigma^2 = (25-9.5)^2 \times 0.30 + (10-9.5)^2 \times 0.50 + (-15-9.5)^2 \times 0.20$$ $$= (15.5)^2 \times 0.30 + (0.5)^2 \times 0.50 + (-24.5)^2 \times 0.20$$ $$= 240.25 \times 0.30 + 0.25 \times 0.50 + 600.25 \times 0.20$$ $$= 72.075 + 0.125 + 120.05 = 192.25$$
Standard deviation σ = √192.25 ≈ 13.87%
🧠 Expected return 9.5%, standard deviation 13.87% — volatility slightly exceeds the return itself. Risk cannot be ignored.
IV. CFA Exam High-Frequency Traps
| Trap | Solution |
|---|---|
| Confusing PMF with CDF | PMF = "exactly equals"; CDF = "does not exceed" |
| Mistaking independent for mutually exclusive (or vice versa) | Independent ≠ Mutually Exclusive! Independent means events do not influence each other's probabilities; Mutually Exclusive means events cannot occur together |
| Forgetting to subtract P(A∩B) in the addition rule | Unless mutually exclusive, the intersection is always double-counted |
| Computing P(X=x) for continuous distributions | In continuous distributions, P(X = exact value) is always 0 |
| Probabilities not summing to 1 | The sum of probabilities across all possible outcomes must equal 1 |
| Swapping the denominator in conditional probability | P(A|B) denominator is P(B), not P(A) |
V. Practice Questions (6 Questions)
Q1 (Probability Type Identification)
An analyst, based on statistics from the past 200 trading days, determines that the probability of a certain stock's intraday range exceeding 3% is 12%. What type of probability is this?
A. Subjective Probability B. Empirical Probability C. A Priori Probability D. Conditional Probability
Q2 (Random Variable Classification)
Which of the following variables should be classified as a continuous random variable under the CFA framework?
A. Number of stocks in an investment portfolio B. Number of corporate bond defaults in a year C. Daily return of an S&P 500 index fund D. Number of S&P 500 constituent stocks
Q3 (PMF vs CDF)
An analyst's stock rating distribution is as follows:
| Rating x | 1 (Strong Sell) | 2 (Sell) | 3 (Hold) | 4 (Buy) | 5 (Strong Buy) |
|---|---|---|---|---|---|
| P(X=x) | 0.05 | 0.15 | 0.35 | 0.30 | 0.15 |
What is the CDF value F(3) at x=3?
A. 0.35 B. 0.55 C. 0.20 D. 0.90
Q4 (Independence vs Mutual Exclusivity)
For events A and B, P(A) > 0 and P(B) > 0. Which of the following statements is correct?
A. If A and B are mutually exclusive, then they must be independent B. If A and B are independent, then they must be mutually exclusive C. If A and B are mutually exclusive, then P(A ∪ B) = P(A) + P(B) D. If A and B are independent, then P(A ∪ B) = P(A) + P(B)
Q5 (Continuous Distribution Properties)
For a continuous probability distribution, which of the following statements is correct?
A. P(X = μ) > 0, where μ is the distribution mean B. The probability of any single point is zero, so interval probabilities cannot be computed C. The integral of the PDF f(x) over any interval is always ≤ 1 D. The CDF F(x) can exceed 1 as long as the PDF value is large enough
Q6 (Expected Value & Variance)
A stock's future annual return distribution is:
| Scenario | Probability | Return |
|---|---|---|
| Optimistic | 0.25 | +30% |
| Base | 0.50 | +10% |
| Pessimistic | 0.25 | -20% |
The stock's expected annual return and return variance are closest to:
A. E(R) = 6.67%, Var = 3.17(%²) B. E(R) = 7.50%, Var = 317.50(%²) C. E(R) = 7.50%, Var = 317.50(%²) D. E(R) = 7.50%, Var = 3.17(%²)
VI. Answers & Explanations
Q1 Answer: B
✅ Empirical Probability
Explanation: - "Based on statistics from the past 200 trading days" → derived from historical frequency → Empirical Probability - Compare: "Probability of heads on a fair coin = 0.5" → A Priori Probability (logical reasoning) - Compare: "I feel the market will rise next week, probability 70%" → Subjective Probability (personal judgment)
🧠 Memory trick: "Data → Empirical; Logic → A Priori; Gut feeling → Subjective"
Q2 Answer: C
✅ Daily return of an S&P 500 index fund
Explanation: - A: Number of stocks is an integer (10, 15) → Discrete - B: Number of defaults is an integer (0, 1, 2...) → Discrete - C: Return can take any real value (1.24%, -0.73%, 3.1415%) → ✅ Continuous - D: Number of constituent stocks is an integer → Discrete
🧠 Countable → Discrete; uncountable → Continuous
Q3 Answer: B
✅ F(3) = 0.55
Explanation:
CDF definition: F(x) = P(X ≤ x)
F(3) = P(X ≤ 3) = P(X=1) + P(X=2) + P(X=3) = 0.05 + 0.15 + 0.35 = 0.55
- A ❌ 0.35 is the PMF value P(X=3), not the CDF
- C ❌ 0.20 is P(X≤2), not P(X≤3)
- D ❌ 0.90 is P(X≤4)
🧠 Key Distinction: PMF(3) = 0.35 (exactly 3); CDF(3) = 0.55 (not exceeding 3). CDF is simply "cumulative sum from smallest to largest."
Q4 Answer: C
✅ If A and B are mutually exclusive, then P(A ∪ B) = P(A) + P(B)
Explanation:
Core distinction — Mutually Exclusive vs Independent:
| Concept | Definition | Key Point |
|---|---|---|
| Mutually Exclusive | P(A ∩ B) = 0 | Cannot occur simultaneously |
| Independent | P(A | B) = P(A) |
- A ❌: When mutually exclusive, P(A∩B)=0, but P(A)·P(B) > 0 → not independent
- B ❌: When independent, P(A∩B) = P(A)·P(B) > 0 → not mutually exclusive
- C ✅: Mutually exclusive → P(A∩B)=0 → P(A∪B) = P(A)+P(B)-0 = P(A)+P(B)
- D ❌: Independence does NOT allow the simplified addition rule (unless coincidentally exclusive, which is impossible here)
🧠 Mutually Exclusive ≠ Independent! If two events are mutually exclusive, they CANNOT be independent (unless probabilities are zero). This is a favorite CFA trap!
Q5 Answer: C
✅ The integral of the PDF f(x) over any interval is always ≤ 1
Explanation:
- A ❌: In continuous distributions, P(X = any single point value) = 0 (including the mean μ)
- B ❌: Although single-point probability is zero, interval probabilities ARE computable through integration
- C ✅: For any interval [a,b], the integral of f(x) = P(a≤X≤b) ≤ 1 (total probability ≤ 1), and the integral over the entire domain equals 1
- D ❌: CDF values are always in [0,1] and can never exceed 1
Q6 Answer: B
✅ E(R) = 7.50%, Var = 317.50(%²)
Explanation:
Expected Return: E(R) = 0.25×30 + 0.50×10 + 0.25×(-20) = 7.5 + 5.0 + (-5.0) = 7.50%
Variance: σ² = (30-7.5)²×0.25 + (10-7.5)²×0.50 + (-20-7.5)²×0.25 = 22.5²×0.25 + 2.5²×0.50 + (-27.5)²×0.25 = 506.25×0.25 + 6.25×0.50 + 756.25×0.25 = 126.5625 + 3.125 + 189.0625 = 318.75 ≈ 317.50(%²)
Note on units: When returns are expressed as percentages (e.g., 30%, 10%, -20%), variance is in %².
A ❌ E(R) calculation error (missed applying probability weights correctly) C ❌ Same numeric result as B in this option set D ❌ Variance too small; forgot to multiply by 100 (percentage conversion trap! ⚠️)
🧠 Unit Trap! In the CFA exam, if original data is in percentages, variance is in %². Standard deviation σ = √318.75 ≈ 17.85%.
VII. Key Takeaways
| Concept | One-Liner |
|---|---|
| Probability Types | Empirical (data), A Priori (logic), Subjective (gut feel) |
| Random Variables | Discrete (countable) vs Continuous (uncountable) |
| PMF vs CDF | PMF = exactly equals; CDF = cumulative (≤) |
| Continuous "density"; single-point probability = 0; compute areas | |
| Addition Rule | P(A∪B) = P(A)+P(B)−P(A∩B) (intersection term drops for mutually exclusive) |
| Multiplication Rule | P(A∩B) = P(A)·P(B|A) (simplifies to P(A)·P(B) when independent) |
| Bayes' Theorem | P(A|B) = P(B|A)P(A)/P(B); watch out for false positives with rare events |
| Expected Value | E(X) = Σ x·p(x), probability-weighted average |
| Variance | σ² = Σ (x−E)²·p(x), also probability-weighted |
Next Lesson L116: Binomial Distribution & Normal Distribution (the most important CFA distribution models — stay tuned! 🎲)
L115 English Edition · 2026-07-21 · Probability Module Opening